Question

(x + 3)² – 4(x + 3) – 5 = 0

Answer 1

`(x + 3)^2 - 4(x + 3) - 5 = 0`

Let  x + 3 = y

then `y^2 - 4y - 5 = 0`

`=> y(y - 5) +1(y -5)= 0`

if y - 5 =    0 or y + 1 = 0

then y = 5 or y = -1

=> x +  3 = 5 or x + 3 = -1

=> x = 2 or x = -4