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Question
`int x^2/sqrt(1 - x^6)dx` = ______.
Options
`-sin^-1 (x^3) + c`
`cos^-1 (x^3) + c`
`sin^-1 (x^3) + c`
`1/3 sin^-1 (x^3) + c`
MCQ
Fill in the Blanks
Solution
`int x^2/sqrt(1 - x^6)dx` = `underlinebb(1/3 sin^-1 (x^3) + c)`.
Explanation:
`int x^2/sqrt(1 - x^6)dx`
∴ Put x3 = t
`\implies` 3x2dx = dt
`\implies` x2dx = `dt/3`
∴ I = `1/3 int dt/sqrt(1 - t^2)`
= `1/3 sin^-1 t + c`
= `1/3 sin^-1(x^3) + c`
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