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Question
Xenon crystallises in fcc lattice and the edge length of unit cell is 620 pm. What is the radius of Xe atom?
Options
438.5 pm
219.2 pm
265.5 pm
536.9 pm
MCQ
Solution
219.2 pm
Explanation:
Given,
Edge length of unit cell (a) = 620 pm
For fcc we know,
Radius (r) = `"a"/(2sqrt(2)) = 620/(2sqrt2)` pm
= `310/1.414` pm
= 219.2 pm
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Packing of Particles in Crystal Lattice
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