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Question
You have learnt how to use math module in Class XI. Write a code where you use the wrong number of arguments for a method (say sqrt() or pow()). Use the exception handling process to catch the ValueError exception.
Solution
Code to show the wrong number of arguments with exception handling.
import math
try:
print(math.sqrt(25,6))
except TypeError:
print("Wrong number of arguments used in sqrt() ")
finally:
print("Okay, Correct it")
Output:
Wrong number of arguments used in sqrt()
Okay, Correct itAPPEARS IN
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What is not true for exception handling?
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While executing the program, if an exception is encountered in try block then execution of the code inside the try block is stopped and:
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Define the following:
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Define the following:
Throwing an exception
Define the following:
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Explain catching exceptions using try and except block.
Predict the output of the Python code given below:
def Diff(N1,N2):
if N1>N2:
return N1-N2
else:
return N2-N1
NUM= [10,23,14,54,32]
for CNT in range (4,0,-1):
A=NUM[CNT]
B=NUM[CNT-1]
print(Diff(A,B),'#', end=' ')“In a Python program, if a break statement is given in a nested loop, it terminates the execution of all loops in one go.”
