Question

10 One mole of a van der Waals' gas obeying the equation `("P" + "a"/"V"^2)`(V - b) = RT undergoes the quasi-static cyclic process which is shown in the P-V diagram. The net heat absorbed by the gas in this process is ______

 

विकल्प

• `1/2("P"_1 - "P"_2)("V"_1 - "V"_2)`

• `1/2("P"_1 + "P"_2)("V"_1 - "V"_2)`

• `1/2("P"_1 + "a"/"V"_1^2 - "P"_2 - "a"/"V"_2^2)("V"_1 - "V"_2)`

• `1/2("P"_1 + "a"/"V"_1^2 + "P"_2 + "a"/"V"_2^2)("V"_1 - "V"_2)`

Answer 1

10 One mole of a van der Waals' gas obeying the equation `("P" + "a"/"V"^2)`(V - b) = RT undergoes the quasi-static cyclic process which is shown in the P-V diagram. The net heat absorbed by the gas in this process is `underline(1/2("P"_1 - "P"_2)("V"_1 - "V"_2))`.

Explanation:

For cyclic process, beat absorbed

= work done

= Area = `1/2("P"_1 - "P"_2)("V"_1 - "V"_2)`