1.56 g of sodium peroxide reacts with water according to the following equation: \[\ce{2Na2O2 + 2H2O -> 4NaOH + O2}\] Calculate the mass of sodium hydroxide formed.

Mol. Mass of Na2O2 = 2 23 + 2 16 = 78 g Mass of 2Na2O2= 156 g 156 g Na2O2 gives = 160 g of NaOH So, 1.56 Na2O2 forms NaOH = `160/156 xx 1.56` = 1.6 g

1.56 g of sodium peroxide reacts with water according to the following equation: 2NaA2OA2+2HA2O⟶4NaOH+OA2 Calculate the mass of sodium hydroxide formed. - Chemistry

प्रश्न

1.56 g of sodium peroxide reacts with water according to the following equation:

$2 Na_{2} O_{2} + 2 H_{2} O ⟶ 4 NaOH + O_{2}$

Calculate the mass of sodium hydroxide formed.

संख्यात्मक

उत्तर

Mol. Mass of Na₂O₂ = 2 23 + 2 16 = 78 g

Mass of 2Na₂O₂= 156 g

156 g Na₂O₂gives = 160 g of NaOH

So, 1.56 Na₂O₂forms NaOH = $\frac{160}{156} \times 1.56$

= 1.6 g

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Numerical Problems of Chemical Equation

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अध्याय 5: Mole concept and Stoichiometry - Exercise 5D [पृष्ठ ९४]

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अध्याय 5 Mole concept and Stoichiometry
Exercise 5D | Q 8 | पृष्ठ ९४

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1.56 g of sodium peroxide reacts with water according to the following equation: 2NaA2OA2+2HA2O⟶4NaOH+OA2 Calculate the mass of sodium hydroxide formed. - Chemistry

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1.56 g of sodium peroxide reacts with water according to the following equation: 2NaA2OA2+2HA2O⟶4NaOH+OA2 Calculate the mass of sodium hydroxide formed. - Chemistry

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