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Question
1.56 g of sodium peroxide reacts with water according to the following equation:
\[\ce{2Na2O2 + 2H2O -> 4NaOH + O2}\]
Calculate the mass of sodium hydroxide formed.
Solution
Mol. Mass of Na2O2 = 2 23 + 2 16 = 78 g
Mass of 2Na2O2= 156 g
156 g Na2O2 gives = 160 g of NaOH
So, 1.56 Na2O2 forms NaOH = `160/156 xx 1.56`
= 1.6 g
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1.56 g of sodium peroxide reacts with water according to the following equation:
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Calculate the volume of oxygen liberated at STP.
