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Concentrated nitric acid oxidizes phosphorus to phosphoric acid according to the following equation: P+5HNOA3⟶HA3POA4+5NOA2+HA2O If 6.2 g of phosphorus was used in the reaction, - Chemistry

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Question

Concentrated nitric acid oxidizes phosphorus to phosphoric acid according to the following equation:

\[\ce{P + 5HNO3 -> H3PO4 + 5NO2 + H2O}\]

If 6.2 g of phosphorus was used in the reaction, calculate the number of moles of phosphorus taken and mass of phosphoric acid formed.

Numerical

Solution

\[\ce{\underset{[Steam 1 mole]}{P + 5HNO3} -> H3PO4 + H2O + 5NO2}\]

1 mole of phosphorus atom = 31 g of phosphorus

31 g of P = 1 mole of P

∴ 6.2 g of P = `(6.2 xx 1)/31`

= 0.2 mole of P

Also, 31 g of phosphorus or 1 mole of phosphorus produces H3PO4

= (3 × 1) + 31 + (4 × 16)

= 98 g of H3PO4

∴ 0.2 mole of P produces = 98 × 0.2

= 19.6 g of H3PO4

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Chapter 5: Mole concept and Stoichiometry - Miscellaneous Exercises [Page 97]

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Selina Concise Chemistry [English] Class 10 ICSE
Chapter 5 Mole concept and Stoichiometry
Miscellaneous Exercises | Q 28. (a) | Page 97

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