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Question
Calculate the mass of ammonia that can be obtained from 21.4 g of NH4Cl by the reaction:
\[\ce{2NH4Cl + Ca(OH)2 -> CaCl2 + 2H2O + 2NH3}\]
Solution
Mol. Mass of 2NH4Cl = 2[14 + (1 × 4) + 35.5] = 2[53.5] = 107 g
107 g NH4Cl gives = 34 g NH3
So, 21.4 g NH4Cl will give = `21.4 × 34/107`
= 6.8 g NH3
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