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Question
Nitrogen and oxygen gas react as illustrated by the equation given below: N2 + O2 → 2NO
Calculate the volume of each reacting gas required to produce 1400cm3 of nitric oxide.
Solution
Given react ion is :
N2 + O2 → 2NO
According to Gay -Lussac's law in the above reaction 1 volume of nitrogen combines with 1 volume of oxygen to produce 2 volumes of nitric oxide.
i .e. N2 + O2 → 2NO
1 vol. 1 vol. 2 vol.
The volume of nitric oxide produced is = 1400cm3.
Let the volumes of nitrogen and oxygen gases be = x
Then, N2 + O2 → 2NO
x x 1400cm3
So, x + x = 1400
2x = 1400
x= 1400/ 2 = 700cm3
Hence the volumes of reacting gases i .e. nitrogen and oxygen is 700 cm3 each.
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