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560 ml of carbon monoxide is mixed with 500 ml of oxygen and ignited. The chemical equation for the reaction is as follows: Calculate the volume of oxygen used and carbon dioxide formed - Chemistry

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Question

560 ml of carbon monoxide is mixed with 500 ml of oxygen and ignited. The chemical equation for the reaction is as follows:

\[\ce{2CO + O2 -> 2CO2}\]

Calculate the volume of oxygen used and carbon dioxide formed in the above reaction.

Numerical

Solution

\[\ce{\underset{2 Vols}{2CO} + \underset{1 Vol}{O2} -> \underset{2 Vols}{2CO2}}\]

2 ml of CO reacts with O2 = 1 ml

560 ml of CO will react with O2 = `1/2 xx 560` = 280 ml

∴ Volume of oxygen used = 280 ml

2 ml of CO produced CO2 = 2 ml

∴ 560 ml of CO will produce CO2 = 560 ml

Volume of oxygen used = 280 ml

Volume of carbon dioxide produced = 560 ml

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Numerical Problems of Chemical Equation
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Chapter 5: Mole concept and Stoichiometry - Miscellaneous Exercises [Page 98]

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Selina Concise Chemistry [English] Class 10 ICSE
Chapter 5 Mole concept and Stoichiometry
Miscellaneous Exercises | Q 46.2 | Page 98

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