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Question
Calculate the percentage of sodium in sodium aluminium fluoride (Na3AlF6) correct to the nearest whole number. (F = 19; Na = 23; Al = 27)
Solution
Molecular mass of Na3AlF6 = 3Na + Al + 6F
= 3 × 23 + 27 + 6 × 19
= 69 + 27 + 114
= 210
Percentage of Na in Na3(AlF6) = `"mass of sodium"/("mass of Na"_3"AlF"_6) xx 100`
= `6/210 xx 100`
= `(69 xx 10)/21`
= `(23 xx 10)/7`
= `230/7`
= 32.9%
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