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Question
Calculate the percentage composition of calcium nitrate [Ca = 40 , Cl = 35.5 , N = 14 , O = 16]
Solution
Calcium nitrate Ca[NO3]
Molecular mass of Ca[NO3]2 = Ca + 2[N2 + 3(O)]
= 40 + 2[14 + 3 × 16]
= 40 + 2[14 + 48]
= 40 + 124
= 164
% of Ca = `40/164 xx 100 = 24.9`
% of N = `28/164 xx 100 = 17.07`
% of O = `96/164 xx 100 = 58.54`
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