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Question
The equation for the burning of octane is:
\[\ce{2C8H18 + 25O2 -> 16CO2 + 18H2O}\]
What volume, at STP, is occupied by 8 moles?
Solution
1 mole of CO2 occupies = 22.4 L at STP.
∴ 8 moles of CO2 will occupy = 22.4 × 8
= 179.2 L at STP
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