मराठी

The equation for the burning of octane is: 2CA8HA18+25OA2⟶16COA2+18HA2O What volume, at STP, is occupied by 8 moles? - Chemistry

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प्रश्न

The equation for the burning of octane is:

\[\ce{2C8H18 + 25O2 -> 16CO2 + 18H2O}\]

What volume, at STP, is occupied by 8 moles?

संख्यात्मक

उत्तर

1 mole of CO2 occupies = 22.4 L at STP.

∴ 8 moles of CO2 will occupy = 22.4 × 8

= 179.2 L at STP

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Numerical Problems of Chemical Equation
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 5: Mole Concept And Stoichiometry - Exercise 8 [पृष्ठ १२२]

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फ्रँक Chemistry - Part 2 [English] Class 10 ICSE
पाठ 5 Mole Concept And Stoichiometry
Exercise 8 | Q 3.2 | पृष्ठ १२२
सेलिना Concise Chemistry [English] Class 10 ICSE
पाठ 5 Mole concept and Stoichiometry
Miscellaneous Exercises | Q 13. (ii) | पृष्ठ ९६

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