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The equation for the burning of octane is: 2CA8HA18+25OA2⟶16COA2+18HA2O How many moles of carbon dioxide are produced when one mole of octane burns? - Chemistry

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Question

The equation for the burning of octane is:

\[\ce{2C8H18 + 25O2 -> 16CO2 + 18H2O}\]

How many moles of carbon dioxide are produced when one mole of octane burns?

Numerical

Solution

2 moles of C8H18 produces = 16 moles of CO2

∴ 1 mole of C8H18  will produce = `16/2`

= 8 moles of CO2

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Chapter 5: Mole Concept And Stoichiometry - Exercise 8 [Page 122]

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Frank Chemistry - Part 2 [English] Class 10 ICSE
Chapter 5 Mole Concept And Stoichiometry
Exercise 8 | Q 3.1 | Page 122
Selina Concise Chemistry [English] Class 10 ICSE
Chapter 5 Mole concept and Stoichiometry
Miscellaneous Exercises | Q 13. (i) | Page 96
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