Advertisements
Advertisements
Question
What mass of Ca will contain the same number of atoms as are present in 3.2 g of S?
Solution
3.2 g of S has number of atoms = `(6.02 xx10^23)/32 xx 3.2`
= 6.02 x 1023 atoms
So, 6.02 x 1023 atoms are present in Ca = 40 g
= `40/(6.02 xx 10^23) xx 6.02 xx 10^22`
= 4g
APPEARS IN
RELATED QUESTIONS
Convert into mole.
22 g of carbon dioxide
A gas cylinder can hold 1 kg of hydrogen at room temperature and pressure.
(a) Find the number of moles of hydrogen present
(b) What weight of CO2can the cylinder hold under similar conditions of temperature and pressure? (H = 1 C = 12, O = 16)
(c) If the number of molecules of hydrogen in the cylinder is X, calculate the number of CO2 molecules in the cylinder with the same conditions of temperature and pressure.
(d) State the law that helped you to arrive at the above result.
Find the number of moles in 10 g of CaCO3.
How many grams of HCl are present in 0.1 mole of it?
How many grams of CO2 is present in 0.1 mole of it?
Calculate the number of atoms in the following:
52 amu of He
Correct the statement, if required.
One mole of chlorine contains 6.023 x 1010 atoms of chlorine.
The difference in the mass of 100 moles each of sodium atoms and sodium ions is 5.48002 g. Compute the mass of an electron.
The visible universe is estimated to contain 1022 stars. How many moles of stars are present in the visible universe?
Compute the difference in masses of 103 moles each of magnesium atoms and magnesium ions.
(Mass of an electron = 9.1×10–31 kg)
