What Mass of Ca Will Contain the Same Number of Atoms as Are Present in 3.2 G of S? - Chemistry

What mass of Ca will contain the same number of atoms as are present in 3.2 g of S?

संख्यात्मक

3.2 g of S has number of atoms = `(6.02 xx10^23)/32 xx 3.2`

= 6.02 x 10²³atoms

So, 6.02 x 10²³atoms are present in Ca = 40 g

= `40/(6.02 xx 10^23) xx 6.02 xx 10^22`

= 4g

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अध्याय 5: Mole concept and Stoichiometry - Exercise 5B [पृष्ठ ८४]

अध्याय 5 Mole concept and Stoichiometry
Exercise 5B | Q 15 | पृष्ठ ८४

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