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Question
Nitrogen and hydrogen react to form ammonia.
\[\ce{N2_{(g)} + 3H2_{(g)}-> 2NH3_{(g)}}\]
If 1000g H2 reacts with 2000g of N2
Will any of the two reactants remain unreacted? If yes, which one and what will be its mass?
Solution
\[\ce{N2_{(g)} + 3H2_{(g)}-> 2NH3_{(g)}}\]
28g 6g 34g
28g of nitrogen requires hydrogen = 6g
2000g of nitrogen requires hydrogen = `6/28 × 2000`
= `3000/7`g
So mass of hydrogen left unreacted =`1000-3000/7`
= `4000/7`
= 571.4g of H2
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