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Question
\[\ce{MnO2 + 4HCl -> MnCl2 + 2H2O + Cl2}\]
0.02 moles of pure MnO2 is heated strongly with conc. HCl. Calculate the mass of acid required.
Solution
For 1 mole MnO2 , acid required = 4 mole of HCl
So, for 0.02 mole, acid required = 4 × 0.02 = 0.08 mole
Mass of HCl = 0.08 x 36.5 = 2.92 g
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