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Question
\[\ce{MnO2 + 4HCl -> MnCl2 + 2H2O + Cl2}\]
0.02 moles of pure MnO2 is heated strongly with conc. HCl. Calculate moles of acid required.
Solution
1 mole MnO2 requires HCl = 4 mole
So, 0.02 mole MnO2 will require = 4 × 0.02
= 0.08 mole
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