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प्रश्न
`int_((-π)/2)^(π/2) log((2 - sinx)/(2 + sinx))` is equal to ______.
विकल्प
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MCQ
रिक्त स्थान भरें
उत्तर
`int_((-π)/2)^(π/2) log((2 - sinx)/(2 + sinx))` is equal to 0.
Explanation:
Let, I = `int_((-π)/2)^(π/2) log((2 - sin x)/(2 + sin x))dx`
f(x) = `log((2 - sinx)/(2 + sinx))`
∴ f(–x) = `((2 - sin(-x))/(2 + sin(-x)))`
= `log((2 + sinx)/(2 - sinx))`
= `-log((2 - sinx)/(2 + sinx))`
= – f(x)
So, f(x) is an odd function.
Hence, `int_(-π/2)^(π/2) f(x)dx` = 0 ...`[∵ "If" f(x) "is an odd function, then" int_-a^a f(x)dx = 0]`
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