हिंदी

3 moles of an ideal gas is compressed from 50 dm3 to 30 dm3 against a constant external pressure of 3.039 × 105 N m−2. The work done in calories is ____________.(1 J = 0.239 cal) -

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प्रश्न

3 moles of an ideal gas is compressed from 50 dm3 to 30 dm3 against a constant external pressure of 3.039 × 105 N m−2. The work done in calories is ____________.
(1 J = 0.239 cal)

विकल्प

  • +30.39 cal

  • +72.63 cal

  • +1452.6 cal

  • +2905.2 cal

MCQ
रिक्त स्थान भरें

उत्तर

3 moles of an ideal gas is compressed from 50 dm3 to 30 dm3 against a constant external pressure of 3.039 × 105 N m−2. The work done in calories is +1452.6 cal.

Explanation:

W = Pext.ΔV (as work is done on the system)

= (3.039 × 105 N m−2) (50 − 30) dm3

= 3.039 × 105 N m−2 × 20 × 10−3 m3

= 6078 N m

= 6078 J

= (6078 × 0.239) cal

= +1452.6 cal

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Expression for Pressure-volume (PV) Work
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