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Question
3 moles of an ideal gas is compressed from 50 dm3 to 30 dm3 against a constant external pressure of 3.039 × 105 N m−2. The work done in calories is ____________.
(1 J = 0.239 cal)
Options
+30.39 cal
+72.63 cal
+1452.6 cal
+2905.2 cal
MCQ
Fill in the Blanks
Solution
3 moles of an ideal gas is compressed from 50 dm3 to 30 dm3 against a constant external pressure of 3.039 × 105 N m−2. The work done in calories is +1452.6 cal.
Explanation:
W = Pext.ΔV (as work is done on the system)
= (3.039 × 105 N m−2) (50 − 30) dm3
= 3.039 × 105 N m−2 × 20 × 10−3 m3
= 6078 N m
= 6078 J
= (6078 × 0.239) cal
= +1452.6 cal
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Expression for Pressure-volume (PV) Work
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