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प्रश्न
`3x-4/7+7/(3x-4)=5/2,x≠4/3`
उत्तर
`3x-4/7+7/(3x-4)=5/2,x≠4/3`
⇒`(3x-4)/7+7/(3x-4)=5/2,x≠4/3`
⇒`( (3x-4)^2+49)/(7(3x-4))=5/2`
⇒` (9x^2-24x+16+49)/(21x-28)`
⇒ `18x^2-48x+130=105x-140`
⇒`2x^2-153x+270=0`
⇒`2x^2-17x+30=0`
⇒`2x(x-6)-5(x-6)=0`
⇒`(x-6)(2x-5)=0`
⇒`x-6=0 or 2x-5=0`
⇒` x=6 or x=5/2`
Hence, 6 and `5/2` are the roots of the given equation.
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