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प्रश्न
Solve :
`3x^2 - 2sqrt6x + 2 = 0`
उत्तर
Given : `3x^2 - 2sqrt6x + 2 = 0`
`=> 3x^2 - sqrt6x - sqrt6x + 2 = 0`
`=> sqrt3x(sqrt3x - sqrt2) - sqrt2(sqrt3x - sqrt2) = 0`
`=> (sqrt3x - sqrt2) (sqrt3x - sqrt2) = 0`
`=> (sqrt3x - sqrt2) = 0 or (sqrt3x - sqrt2) = 0`
`=> x = sqrt(2/3), sqrt(2/3)`
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