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प्रश्न
`48x^2-13x1=0`
उत्तर
Given:
`48x^2-13x-1=0`
⇒` 48x^2-(16x-3x)-1=0`
⇒`48x^2-16x+3x-1=0`
⇒`16x(3x-1)+1(3x-1)=0`
⇒`(16x+1)(3x-1)=0`
⇒`16x+1=0 or 3x-1=0`
⇒`x=-1/16 or x=1/3`
Hence, the roots of the equation are `-1/16` and `1/3`
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