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प्रश्न
Solve the following equation using the formula:
`2/3x = -1/6x^2 - 1/3`
उत्तर
`2/3x = -1/6x^2 - 1/3`
`\implies` 4x = – x2 – 2
`implies` x2 + 4x + 2 = 0
Here a = 1, b = 4 and c = 2
Then `x = (-b +- sqrt(b^2 - 4ac))/(2a)`
= `(-(-4) +- sqrt((4)^2-4(1)(2)))/(2(1))`
= `(-4 +- sqrt(8))/2`
= `(-4 +- 2sqrt(2))/2`
= `-2 +- sqrt(2)`
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