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प्रश्न
`x^2+3sqrt3-30=0`
उत्तर
We write, `3sqrt3x=5sqrt3x-2sqrt3x as x^2xx(-30)=-30x^2=5sqrt3x x(-2sqrt3x)`
∴`x^2+3sqrt3x-30=0`
⇒`x^2+5sqrt3x-2sqrt3x-30=0`
⇒ `x(x+5sqrt3)-2sqrt3(x+5sqrt3)=0`
⇒`(x+5sqrt3) (x-2sqrt3)=0`
⇒`x+5sqrt3=0 or x-2sqrt3=0`
⇒`x=-5sqrt3 or x=2sqrt3`
Hence, the roots of the given equation are `-5 sqrt3` and `2sqrt3`
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