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प्रश्न
`x^2-(sqrt3+1)x+sqrt3=0`
उत्तर
`x^2-(sqrt3+1)x+sqrt3=0`
⇒`x^2-sqrt3x-x+sqrt3=0`
⇒`x(x-sqrt3)-1 (x-sqrt3)=0`
⇒`(x-sqrt3)(x-1)=0`
⇒`x-sqrt3 or x-1=0`
⇒` x= sqrt3 or x=1`
Hence, 1 and `sqrt3` are the roots of the given equation.
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