Advertisements
Advertisements
प्रश्न
Solve the following equation using the formula:
`x^2 - 6 = 2sqrt(2)x`
उत्तर
`x^2 - 6 = 2sqrt(2)x`
`\implies x^2-2sqrt2x-6=0`
Here a = 1, b = `-2sqrt(2)` and c = − 6
Then `x = (-b +- sqrt(b^2 - 4ac))/(2a)`
= `(-(-2sqrt2) +- sqrt((-2sqrt(2))^2 - 4(1)(-6)))/(2(1))`
= `(2sqrt(2) +- sqrt(32))/2`
= `(2sqrt(2) +- 4sqrt(2))/2`
= `(2sqrt(2) + 4sqrt(2))/2` and `(2sqrt(2) - 4sqrt(2))/2`
= `(6sqrt(2))/2` and `(-2sqrt(2))/2`
= `3sqrt(2)` and `-sqrt(2)`
APPEARS IN
संबंधित प्रश्न
Solve the equation 4x2 – 5x – 3 = 0 and give your answer correct to two decimal places
Without solving the following quadratic equation, find the value of m for which the given equation has equation has real and equal roots.
`x^2 + 2(m - 1)x + (m + 5) = 0`
Solve `5/(x - 2) - 3/(x + 6) = 4/x`
`sqrt3x^2+11x+6sqrt3=0`
`5x^2+13x+8=0`
An ordinary train takes 3 hours less for a j ourney of 360kms when its speed is increased by 1 Okm/ hr.Fnd the usual speed of the train.
If p – 15 = 0 and 2x2 + px + 25 = 0; find the values of x.
Examine whether the equation 5x² -6x + 7 = 2x² – 4x + 5 can be put in the form of a quadratic equation.
Solve the following equation by using formula :
`x(3x + 1/2)` = 6
Write the given quadratic equation in standard form.
m (m – 6) = 9
