Advertisements
Advertisements
प्रश्न
Examine whether the equation 5x² -6x + 7 = 2x² – 4x + 5 can be put in the form of a quadratic equation.
उत्तर
5x² - 6x + 7 = 2x² – 4x + 5
⇒ 5x² - 6x + 7 - 2x2 + 4x - 5 = 0
⇒ 3x2 - 2x + 2 = 0.
APPEARS IN
संबंधित प्रश्न
Write the quadratic equation whose roots are ‒2 and ‒3.
(x + 5)(x - 2) = 0, find the roots of this quadratic equation
Check whether the following is the quadratic equation:
x2 - 2x = (-2)(3 - x)
Check whether the following is the quadratic equation:
x2 + 3x + 1 = (x - 2)2
Represent the following situation in the form of a quadratic equation:
The product of two consecutive positive integers is 306. We need to find the integers.
Solve the following equation using the formula:
x2 + 2x – 6 = 0
`x^2-(sqrt3+1)x+sqrt3=0`
`4^((x+1))+4^((1-x))=10`
`2^2x-3.2^((x+2))+32=0`
Solve :
`3x^2 - 2sqrt6x + 2 = 0`
