Question

`int_(-5)^5 log ((7 - x)/(7 + x))`dx = ?

विकल्प

• 5

• -5

• 0

• 10

Answer 1

0

Explanation:

Let I = `int_(-5)^5 log ((7 - x)/(7 + x))`dx

f(x) = `log ((7 - x)/(7 + x))`

f(- x) = `log ((7 - x)/(7 + x))`

f(- x) = `log ((7 - x)/(7 + x))^-1`

= - `log ((7 - x)/(7 + x))`

f(- x) = - f(x)

∴ f(x) is an odd function

∴ l = 0