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70 Calories of Heat Are Required to Raise the Temperature of 2 Mole of an Ideal Gas at Constant Pressure from 30° C to 35° C. - Physics

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प्रश्न

70 calories of heat are required to raise the temperature of 2 mole of an ideal gas at constant pressure from 30° C to 35° C. The amount of heat required to raise the temperature of the same gas through the same range at constant volume is

विकल्प

  • 30 calories

  • 50 calories

  • 70 calories

  • 90 calories

MCQ

उत्तर

50 calories
It is given that 70 calories of heat are required to raise the temperature of 2 mole of an ideal gas at constant pressure from 30° C to 35° C. Also, specific heat at constant pressure,

`"C"_"P" = (triangle Q)/(ntriangleT)`

`=> "C"_"P" = 70/ (2 xx (35-30)`

`=> "C"_"P" =70/(2 xx 5)`

`=> "C"_"P" = 7 "calories" -" mol" ^-1K^-1`

For an ideal gas , 

CP - CV = R = 8.314 J - mol -1 K-1 ≃ 2 calories mol-1K-1 

⇒ CV =CP -R

⇒ CV = (7-2) calories - mol-1 K-1

⇒ CV = 5 calories - mol-1 K-1

⇒ CV = `(triangle "Q")/(ntriangle"T")`

`=> 5 = (triangle "Q")/(2 xx (35-30)`

⇒ Δ Q = 5 × 2 × (35-30)

⇒ Δ Q = 5 × 2 × 5

⇒ Δ Q = 50 calories

Therefore, 50 calories need to be supplied to raise the temperature of 2 moles of gas from 30-35 oC at constant volume.

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Molecular Nature of Matter
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Specific Heat Capacities of Gases - MCQ [पृष्ठ ७६]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
अध्याय 5 Specific Heat Capacities of Gases
MCQ | Q 5 | पृष्ठ ७६

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