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A bag contains 8 red and some blue balls. One ball is drawn at random from the bag. If ratio of probability of getting red ball and blue ball is 2 : 5, then find the number of blue balls. - Algebra

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प्रश्न

A bag contains 8 red and some blue balls. One ball is drawn at random from the bag. If ratio of probability of getting red ball and blue ball is 2:5, then find the number of blue balls.

योग

उत्तर

Suppose the number of blue balls = x

∴ n(Blue ball) = x

Number of red balls = 8

∴ n(Red ball) = 8

Total number of balls = 8 + x

∴ n(T) = 8 + x

P(Blue ball drawn) = `(n("Blue ball"))/(n(T))`

= `x/(8 + x)`

P(Red ball drawn) = `(n("Red ball"))/(n(T))`

=`8/(8 + x)`

According to the given condition

`(P("Blue ball drawn"))/(P("Red ball drawn")) = 5/2`

∴ `x/((8 + x)/8) = 5/2`

∴ `x/8 = 5/2`

∴ x = 20

Hence, the number of blue balls is 20.

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