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प्रश्न
A bar magnet of mass 120 g in the form of a rectangular parallelepiped, has dimensions l = 40 mm, b = 10 mm and h = 80 mm, with its dimension ‘h’ vertical, the magnet performs angular oscillations in the plane of the magnetic field with period π seconds. If the magnetic moment is 3.4 Am2, determine the influencing magnetic field.
उत्तर
Given:
- m = 120 g = 0.12 kg
- l = 4 × 10-2 m
- b = 10-2 m
- h = 80 mm = 8 × 10-2 m
- T = π sec
- μ = 3.4 Am2
To find: B
T = `2pisqrt(I/(muB))`
where, I = `m[(l^2 + b^2)/12]`
I = `0.12[(1600 xx 100)/12] xx 10^-6`
I = `1.7 xx 10^-5` Am2
∴ I = `2pisqrt(l/(muB))`
`pi = 2pisqrt((1.7 xx 10^5)/(3.4 xx B))`
∴ B = 2 × 10-5 Wb/m2
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