हिंदी

A body with mass 5 kg is acted upon by a force F = (–3i^+4j^) N. If its initial velocity at t = 0 is v = (6i^-12j^) ms–1, the time at which it will just have a velocity along the y-axis is ______. - Physics

Advertisements
Advertisements

प्रश्न

A body with mass 5 kg is acted upon by a force F = `( –3hati + 4hatj)` N. If its initial velocity at t = 0 is v = `(6hati - 12hatj)` ms–1, the time at which it will just have a velocity along the y-axis is ______.

विकल्प

  • never

  • 10 s

  • 2 s

  • 15 s

MCQ
रिक्त स्थान भरें

उत्तर

A body with mass 5 kg is acted upon by a force F = `( –3hati + 4hatj)` N. If its initial velocity at t = 0 is v = `(6hati - 12hatj)` ms–1, the time at which it will just have a velocity along the y-axis is 10 s.

Explanation:

Since `veca = (vecF)/m` hence, we have `veca = 1/5 (- 3hati + 4hatj) N`

Now, since the x-component of the final velocity is zero,

Hence, `v_x = u_x + a_xt`

0 = `6hati + (- 3hati)/5 t`

That gives us t = 10 s.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Laws of Motion - Exercises [पृष्ठ ३१]

APPEARS IN

एनसीईआरटी एक्झांप्लर Physics [English] Class 11
अध्याय 5 Laws of Motion
Exercises | Q 5.8 | पृष्ठ ३१
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×