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प्रश्न
उत्तर
30. Let C be the specific heat capacity of water.
Let final temperature of the mixture be 8°C.
Heat energy lost by hot water = Heat energy gained by cold water
2 x C x (80 - 8) = 8 x C x (8 - 25)
or, 2(80 - 8) = 8 (8 - 25)
or,80 - 8 = 48 - 100
or, 58 = 180
0 = 36
So, the final temperature of water will be 36°C.
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संबंधित प्रश्न
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