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प्रश्न
(a) Calculate the total resistance across AB.
(b) If a cell of e.m.f 2.4 V with negligible internal resistance is connected across AB then calculate the current drawn from the cell.
उत्तर
(a) Resistors 3 Ω and 5 Ω are in series. The equivalent resistance of these two is 8 Ω.
Now, this 8 Ω is connected with another 8 Ω resistors in parallel.
The equivalent resistance of these two is
`= (8 xx 8)/(8 + 8)`
`= 64/16`
= 4 Ω.
Thus, the total resistance across AB is 4 Ω.
(b) If a cell of e.m.f 2.4 V with negligible internal resistance is connected across AB then the current drawn from the cell is
`= ("Voltage" ("V"))/("equivalent resistance" ("R"))`
`= 2.4/4`
= 0.6 A.
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संबंधित प्रश्न
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- the current drawn from the cell.
- the p.d. across the cell.
- voltage drop inside the cell.
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- Under what condition is the e.m.f. of a cell equal to its terminal voltage?
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A battery of e.m.f. 15 V and internal resistance 3 ohm is connected to two resistors of resistances 3 ohm and 6 ohm is series Find:
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What is the colour code for the insulation on the earth wire?
Four cells, each of e.m.f. 1.5 V and internal resistance 2.0 ohms are connected in parallel. The battery of cells is connected to an external resistance of 2.5 ohms. Calculate:
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(ii) The current flowing in the external circuit.
(iii) The drop in potential across-the terminals of the cells.
Four cells each of e.m.f. 2V and internal resistance 0.1 Ω are connected in series to an ammeter of negligible resistance, a 1.6 Ω resistor and an unknown resistor R1. The current in the circuit is 2A. Draw a labelled diagram and calculate:
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(ii) Total e.m.f.
(iii) The value of R1 and
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- Calculate the total resistance of the circuit.
- Calculate the current drawn from the cell.
- State whether the current through 10 Ω resistor is greater than, less than or equal to the current through the 12 Ω resistor.
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