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प्रश्न
A capacitor of unknown capacitance is connected across a battery of 'V' volt. The charge stored in it is 'Q' coulomb. When the potential across the capacitor is reduced by 'V' volt, the charge stored in it becomes Q' coulomb. The potential V is ______
विकल्प
`(QV^')/((Q - Q^'))`
`(QV^')/((Q + Q^'))`
`((Q - Q^'))/(QV^')`
`((Q + Q^'))/(QV^')`
MCQ
रिक्त स्थान भरें
उत्तर
A capacitor of unknown capacitance is connected across a battery of 'V' volt. The charge stored in it is 'Q' coulomb. When the potential across the capacitor is reduced by 'V' volt, the charge stored in it becomes Q' coulomb. The potential V is `underline((QV^')/((Q - Q^')))`.
Explanation:
Q = CV
Q' = C(V - V')
∴ C = `Q^'/(V - V^')`
∴ Q = `Q^'/(V - V^') . V`
QV - QV' = Q'V
V(Q - Q') = QV'
V = `(QV^')/(Q - Q^')`
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