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प्रश्न
A capacitor of unknown capacitance is connected across a battery of 'V' volt. The charge stored in it is 'Q' coulomb. When the potential across the capacitor is reduced by 'V' volt, the charge stored in it becomes Q' coulomb. The potential V is ______
पर्याय
`(QV^')/((Q - Q^'))`
`(QV^')/((Q + Q^'))`
`((Q - Q^'))/(QV^')`
`((Q + Q^'))/(QV^')`
MCQ
रिकाम्या जागा भरा
उत्तर
A capacitor of unknown capacitance is connected across a battery of 'V' volt. The charge stored in it is 'Q' coulomb. When the potential across the capacitor is reduced by 'V' volt, the charge stored in it becomes Q' coulomb. The potential V is `underline((QV^')/((Q - Q^')))`.
Explanation:
Q = CV
Q' = C(V - V')
∴ C = `Q^'/(V - V^')`
∴ Q = `Q^'/(V - V^') . V`
QV - QV' = Q'V
V(Q - Q') = QV'
V = `(QV^')/(Q - Q^')`
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