Question

A capillary tube is vertically immersed in water, water raises upto height 'h₁'. When the whole arrangement is taken upto depth 'd' in a mine, the water level rises upto height 'h₂'. The ratio of `"h"_1/"h"_2` is _______. (R = radius of earth)

विकल्प

• `(1 - "2D"/"R")`

• `(1 - "d"/"R")`

• `(1 + "2D"/"R")`

• `(1 + "d"/"R")`

Answer 1

A capillary tube is vertically immersed in water, water raises upto height 'h₁'. When the whole arrangement is taken upto depth 'd' in a mine, the water level rises upto height 'h₂'. The ratio of `"h"_1/"h"_2` is `underline((1 - "d"/"R"))`.

Explanation:

hg = constant    `"h" prop 1/"g"`

`"h"_1/"h"_2 = "g"_2/"g"_1 = ("g"(1 - "d"/"R"))/"g" = 1 - "d"/"R"`