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Question
A capillary tube is vertically immersed in water, water raises upto height 'h1'. When the whole arrangement is taken upto depth 'd' in a mine, the water level rises upto height 'h2'. The ratio of `"h"_1/"h"_2` is _______. (R = radius of earth)
Options
`(1 - "2D"/"R")`
`(1 - "d"/"R")`
`(1 + "2D"/"R")`
`(1 + "d"/"R")`
MCQ
Fill in the Blanks
Solution
A capillary tube is vertically immersed in water, water raises upto height 'h1'. When the whole arrangement is taken upto depth 'd' in a mine, the water level rises upto height 'h2'. The ratio of `"h"_1/"h"_2` is `underline((1 - "d"/"R"))`.
Explanation:
hg = constant `"h" prop 1/"g"`
`"h"_1/"h"_2 = "g"_2/"g"_1 = ("g"(1 - "d"/"R"))/"g" = 1 - "d"/"R"`
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