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प्रश्न
A car of mass 1000 kg develops a force of 500 N over a distance of 49 m. If initially, the car is at rest find
- Final velocity
- time for which it accelerates.
उत्तर
Mass of car = m = 1000 kg
Force = F = 500 N
Acceleration of car = a = `"F"/"m"=500/1000` = 0.5 ms−2
Initially velocity = u = 0
Distance covered = S = 49 m
Final velocity = v = ?
Time = t = ?
1. v2 – m2 = 2a S
v2 – (0)2 = 2 (0.5) (49)
v2 = 49
v = 7 ms−1
2. v = u + at
7 = 0 + 0.5t
0.5 t = 7
t = `7/0.5` = 14 s
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