Question

A circular coil of radius R has a resistance of 40 Ω. Figure shows two points P and Q on the circumference separated by a distance ${\displaystyle \frac{\pi \text{R}}{2}}$, which are connected to a 16 V battery with internal resistance of 0.5 Ω. What is the value of current I flowing through the circuit?

विकल्प

• 3A

• 2A

• 1A

• 0.5A

Answer 1

2A

Explanation:

The total resistance between points P and Q.

R_PQ = (30 || 10 + 0.5)

${\displaystyle =\frac{30\times 10}{30+10}+0.5=8 \Omega }$

The current flowing through the circuit,

V = ${\displaystyle {\text{IR}}_{\text{PQ}}}$

${\displaystyle \Rightarrow \text{I}=\frac{\text{V}}{{\text{R}}_{\text{PQ}}}}$

where, V is the voltage of source.

∴ I = ${\displaystyle \frac{16\text{V}}{8\Omega }}$ = 2A