Question

A circular coil of radius R has a resistance of 40 Ω. Figure shows two points P and Q on the circumference separated by a distance `(pi"R")/2`, which are connected to a 16 V battery with internal resistance of 0.5 Ω. What is the value of current I flowing through the circuit?

Options

• 3A

• 2A

• 1A

• 0.5A

Answer 1

2A

Explanation:

The total resistance between points P and Q.

R_PQ = (30 || 10 + 0.5)

`= (30 xx 10)/(30 + 10) + 0.5 = 8  Omega`

The current flowing through the circuit,

V = `"IR"_"PQ"`

`=> "I" = "V"/"R"_"PQ"`

where, V is the voltage of source.

∴ I = `(16"V")/(8 Omega)` = 2A