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A Coin is Tossed 5 Times. What is the Probability of Getting at Least 3 Heads? - Mathematics

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प्रश्न

A coin is tossed 5 times. What is the probability of getting at least 3 heads?

 
योग

उत्तर

\[\text{ Let X denote the number of heads in 5 tosses }  . \]
\[ \text{ X follows a binomial distribution with n } = 5; p = \text{ probability of getting a head } = \frac{1}{2}\text{ and }  q = 1 - p = \frac{1}{2}\]
\[P(X = r) =^{5}{}{C}_r \left( \frac{1}{2} \right)^r \left( \frac{1}{2} \right)^{5 - r} , r = 0, 1, 2 . . . 5\]
\[\text{ The required probability = P(getting at least 3 heads } )\]
\[ = P(X \geq 3) \]
\[ = P(X = 3) + P(X = 4) + P(X = 5)\]
\[ = ^{5}{}{C}_3 \left( \frac{1}{2} \right)^3 \left( \frac{1}{2} \right)^{5 - 3} + ^{5}{}{C}_4 \left( \frac{1}{2} \right)^1 \left( \frac{1}{2} \right)^{5 - 1} + ^{5}{}{C}_5 \left( \frac{1}{2} \right)^5 \left( \frac{1}{2} \right)^{5 - 0} \]

\[= 10 \left( \frac{1}{2} \right)^5 + 5 \left( \frac{1}{2} \right)^5 + 1 \left( \frac{1}{2} \right)^5 \]

\[ = \left( \frac{1}{2} \right)^5 (10 + 5 + 1) \]

\[ = \left( \frac{1}{2} \right)^5 \times 16 \]

\[ = \frac{1}{2}\]

 

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अध्याय 33: Binomial Distribution - Exercise 33.1 [पृष्ठ १३]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 33 Binomial Distribution
Exercise 33.1 | Q 2 | पृष्ठ १३

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