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प्रश्न
A current-carrying conductor of a certain length, kept perpendicular to the magnetic field experiences a force F. What will be the force if the current is increased four times, the length is halved and the magnetic field is tripled?
एक पंक्ति में उत्तर
उत्तर
F = I L B = (4I) ×`("L"/"2")` × (3 B) =6 F
Therefore, the force increases six times.
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