Advertisements
Advertisements
Question
A current-carrying conductor of a certain length, kept perpendicular to the magnetic field experiences a force F. What will be the force if the current is increased four times, the length is halved and the magnetic field is tripled?
One Line Answer
Solution
F = I L B = (4I) ×`("L"/"2")` × (3 B) =6 F
Therefore, the force increases six times.
shaalaa.com
Is there an error in this question or solution?
