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प्रश्न
A cylindrical tub of radius 16 cm contains water to a depth of 30 cm. A spherical iron ball is dropped into the tub and thus level of water is raised by 9 cm. What is the radius of the ball?
उत्तर
Let r be the radius of the iron ball
Then, Volume of iron ball = Volume of water raised in the hub
⇒`4/3πr^3=πr^2h`
⇒`4/3r^3=(16)^2xx9`
⇒`r^3=(27xx16xx16)/4`
⇒ `r^3=1728`
⇒ r=12cm
Therefore, radius of the ball = 12cm.
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